ഒരു സമാന്തര ശ്രേണിയിൽ 15 പദങ്ങളുണ്ട്. അതിന്റെ ആദ്യ പദം 5 ഉം അവയുടെ ആകെത്തുക 390 ഉം ആണ്. മധ്യപദം കണ്ടെത്തുക.

  1. 23
  2. 26
  3. 28
  4. 32

Answer (Detailed Solution Below)

Option 2 : 26
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ഇവിടെ, n = 15; a = 5 ഉം ആകെത്തുക = 390 ഉം

പൊതു വ്യത്യാസം കണ്ടെത്താൻ ആകെത്തുക സൂത്രവാക്യം പ്രയോഗിക്കുമ്പോൾ,

\(390 = \frac{{15}}{2}\left[ {2 \times 5 + 14d} \right] = 15 \times \left( {5 + 7d} \right)\)

⇒ 5 + 7d = 26

⇒ d = 3

∴ മധ്യപദം = 8-ആം പദം = a + 7d = 5 + 21 = 26

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