Question
Download Solution PDFഒരു സമാന്തര ശ്രേണിയിൽ 15 പദങ്ങളുണ്ട്. അതിന്റെ ആദ്യ പദം 5 ഉം അവയുടെ ആകെത്തുക 390 ഉം ആണ്. മധ്യപദം കണ്ടെത്തുക.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFഇവിടെ, n = 15; a = 5 ഉം ആകെത്തുക = 390 ഉം
പൊതു വ്യത്യാസം കണ്ടെത്താൻ ആകെത്തുക സൂത്രവാക്യം പ്രയോഗിക്കുമ്പോൾ,
⇒ \(390 = \frac{{15}}{2}\left[ {2 \times 5 + 14d} \right] = 15 \times \left( {5 + 7d} \right)\)
⇒ 5 + 7d = 26
⇒ d = 3
∴ മധ്യപദം = 8-ആം പദം = a + 7d = 5 + 21 = 26
Last updated on May 26, 2025
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