वाऱ्याने एक खांब तुटला ज्याचा वरचा भाग पायापासून 90 मीटर अंतरावर 30° कोनात जमिनीला मिळतो. खांबाची एकूण उंची किती होती?

  1. 30√3
  2. 60√3
  3. 90√3
  4. 45√3

Answer (Detailed Solution Below)

Option 3 : 90√3
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RRB NTPC CBT-I Official Paper (Held On: 4 Jan 2021 Shift 1)
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Detailed Solution

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F1 Ashish 23.9.20 Pallavi D4

सूत्र:

tanθ = लंब/पाया

cosθ = पाया/कर्ण

गणना:

ध्रुवाचा तुटलेला बिंदू A आहे. आणि बिंदू C हा एक बिंदू आहे जेथे ध्रुव जमिनीवर येतो.

खांबाची एकूण लांबी = BA + AC

BC = 90

tan30° = AB/BC

⇒ 1/√3 = AB/90

⇒ AB = 90/√3

⇒ AB = 30√3

पुन्हा,

cos30° = BC/AC

⇒ √3/2 = 90/AC

⇒ AC = 90 × (2/√3)

⇒ AC = 60√3

∴ खांबाची एकूण उंची = 30√3 + 60√3 = 90√3 मीटर

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