Question
Download Solution PDFएक चोर दुपारी 3:30 वाजता एक कार चोरतो आणि 80 किमी/तास वेगाने कार चालवतो. दुपारी 4 वाजता चोरीचा प्रकार उघडकीस येतो आणि मालक 90 किमी/तास वेगाने दुसऱ्या कारमधून निघतो. तो चोराला किती वाजता पकडेल?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिलेल्याप्रमाणे:
चोराचा वेग = 80 किमी/तास, मालकाचा वेग = 90 किमी/तास, वेळेचे अंतर= 0.5 तास
सूत्र:
वेळ = अंतर/वेग
गणना:
चोराने 0.5 तासात पार केलेले अंतर = 80 × 0.5 = 40 किमी
मालक ते चोर यांचा सापेक्ष वेग = 90 - 80 = 10 किमी/तास
पकडण्याचा वेळ = 40/10 = 4 तास
म्हणून, मालक चोराला 8:00 वाजता पकडेल.
Last updated on Jun 30, 2025
-> The Staff Selection Commission has released the SSC GD 2025 Answer Key on 26th June 2025 on the official website.
-> The SSC GD Notification 2026 will be released in October 2025 and the exam will be scheduled in the month of January and February 2026.
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