Question
Download Solution PDFABCD हा चक्रीय चौकोन आहे. कर्ण BD आणि AC एकमेकांना E वर छेदतात. जर ∠BEC = 138° आणि ∠ECD = 35°, तर ∠BAC चे मोजमाप काय आहे?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिले:
∠BEC = 138° आणि ∠ECD = 35°
वापरलेली संकल्पना:
चक्रीय चतुर्भुज मध्ये समान कमानीवरील कोन नेहमी समान असतात
गणना:
∠BEC आणि ∠CED समान सरळ रेषांवर आहेत
∠BEC = 138°
∠CED = 180° - 138°
⇒ ∠CED = 42°
ΔCDE मध्ये, ∠CED = 42° आणि ∠DCE = 35°
∠CDE = 180° - (42° + 35°)
∠CDE = 103°
∠BAC आणि ∠BDC एकाच चाप BC वर आहेत
आपल्याला माहित आहे की चक्रीय चतुर्भुजांमध्ये एकाच कमानीवरील कोन नेहमी समान असतात.
∠BAC = 103°
∴ ∠BAC चे माप 103° आहे
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