Question
Download Solution PDFजर ax + 5y = 8 ची तिरपी रेषा -4/3 असेल तर a चे मूल्य काय आहे?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिलेल्याप्रमाणे:
ax + 5y = 8
गणना:
ax + 5y = 8
⇒ y = -ax/5 + 8/5
त्याची तुलना y = mx + c, जेथे m = तिरपी रेषा
तर, m = -a/5
⇒ तिरपी रेषा= -a/5 = -4/3 (दिलेल्याप्रमाणे)
⇒ a/5 = 4/3
∴ a = 20/3
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