Question
Download Solution PDFदोन शहरे A आणि B एका सरळ मार्गावर 135 किमी अंतरावर आहेत. एक कार A पासून सकाळी 8 वाजता सुरू होते आणि B च्या दिशेने 25 किमी/ताशी प्रवास करते. दुसरी कार सकाळी 9 वाजता B पासून सुरू होते आणि 30 किमी/ताशी वेगाने A च्या दिशेने जाते. ते किती वाजता भेटतील?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFबरोबर उत्तर आहे (a.11m)
महत्त्वाचे मुद्दे -
समजा ते सकाळी 8 नंतर x तासांनी भेटतात
x तासांनंतर A ने व्यापलेले अंतर = 25x किमी.
(x-1) तासांनंतर B ने कापलेले अंतर = 30(x-1) किमी.
\(अंतर = वेळ * वेग\)
135 = 25x + 30(x-1)
135 = 25x + 30x - 30
135 = 55x - 30
135 + 30 = 55x
१६५/५५ = x
म्हणजे, x = 3 तास
दोन गाड्या 3 तासांनंतर भेटतील; सकाळी ८ वाजता + ३ तास = सकाळी ११
त्यामुळे बरोबर उत्तर सकाळी ११ वाजता आहे
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