\(\sqrt 2 ,\sqrt {10} ,5\sqrt 2 \) ………. వరుసలో 7వ పదం?

  1. \(\frac{{n\left( {a + b} \right)}}{2}\)

  2. \(25\sqrt 2 \)
  3. 125
  4. \(125\sqrt 2 \)

Answer (Detailed Solution Below)

Option 4 : \(125\sqrt 2 \)
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నిష్పత్తి పరిధి యొక్క మొదటి పదం = √2

= √2

సాధారణ నిష్పత్తి = √10/√2 = √5

⇒ 7పదం= \(a{r^6} = \sqrt 2 \times {\left( {\sqrt 5 } \right)^6} = 125\sqrt 2 \)

∴ 7వ పదం = 125√2

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