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ఒక వస్తువు x = 0 m మరియు t = 0 s వద్ద నిశ్చల స్థితి నుండి ప్రారంభమవుతుంది. ఇది x-అక్షం వెంట 2మీ/సె2 స్థిరమైన త్వరణంతో కదులుతుంది. సమయం 1 సె మరియు 5 సె మధ్య దాని సగటు వేగం ఎంత?

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RRB ALP Electrician 22 Jan 2019 Official Paper (Shift 1)
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  1. 2 మీ/సె
  2. 8 మీ/సె
  3. 6 మీ/సె
  4. 4 మీ/సె

Answer (Detailed Solution Below)

Option 3 : 6 మీ/సె
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Detailed Solution

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సరైన సమాధానం 6 మీ/సె.

భావన:

  • సగటు వేగం = మొత్తం స్థానభ్రంశం/మొత్తం సమయ వ్యవధి

ఇచ్చిన:

  • సమయ విరామం = 5సె- 1సె= 4సె,
  • ప్రారంభ వేగం u=0, మరియు
  • త్వరణం a = 2 మీ/సె2

లెక్కింపు:

  • చలన మొదటి సమీకరణం ప్రకారం:
    • v (చివరి వేగం) = u + వద్ద
    • v = 0 + (2 x 1)
    • v (1 సెకను వద్ద) = 2 మీ/సె
  • కదలిక యొక్క రెండవ సమీకరణం ప్రకారం:
  • s (స్థానభ్రంశం)= ut + 1/2 వద్ద2
    • = 2 x 4 + 1/2 x 2 x 16
  • మొత్తం స్థానభ్రంశం = 24 మీ
    సగటు వేగం= మొత్తం స్థానభ్రంశం/మొత్తం సమయ వ్యవధి
    • 24 మీ / 4 s
    • 6 మీ/సె
  • సమయం 1 సె మరియు 5 సె = 6 మీ/సె మధ్య సగటు వేగం
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