మీథేన్లో మోల్ ద్వారా కార్బన్ శాతం కూర్పు:

This question was previously asked in
JEE Mains Previous Paper 1 (Held On: 08 Apr 2019 Shift 2)
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  1. 75%
  2. 80%
  3. 25%
  4. 20%

Answer (Detailed Solution Below)

Option 4 : 20%
Free
JEE Main 04 April 2024 Shift 1
90 Qs. 300 Marks 180 Mins

Detailed Solution

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కాన్సెప్ట్:

CH4 (మీథేన్)లో 'C' యొక్క మోల్ % =

లెక్కింపు:

1 కార్బన్ మరియు 4 హైడ్రోజన్ అనే 5 పరమాణువులలో మీథేన్‌లో ఒక కార్బన్ అణువు ఉంది

= 0.2 × 100 = 20%

శాత కూర్పు అనేది సమ్మేళనంలోని ప్రతి మూలకం యొక్క ద్రవ్యరాశి శాతం.

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