The IUPAC Name of the compound

CH3 – CH = CH – C ≡ CH is

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  1. Pent- 2 en-4-yne
  2. Pent-1-en-4-yne
  3. Pent-3-en-1-yne
  4. Pent-2-en-5-yne

Answer (Detailed Solution Below)

Option 3 : Pent-3-en-1-yne
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CONCEPT:

Nomenclature of Alkenes and Alkynes

  • The IUPAC nomenclature system is a standardized method for naming chemical compounds.
  • When naming compounds with both double (alkene) and triple (alkyne) bonds, certain rules must be followed:
    • Identify the longest continuous carbon chain that contains both the double and triple bonds.
    • Number the chain from the end nearest to the first multiple bond (double or triple).
    • Indicate the positions of the double and triple bonds using the appropriate locants (numbers).
    • Write the name as a single word with the position and type of the bonds in the format: [prefix] - [locant]-[alken]-[locant]-[yne].

EXPLANATION:

  • For the compound CH3-CH=CH-C≡CH:
    • The longest carbon chain containing both the double and triple bonds has 5 carbons.
    • Numbering from the end closest to the first multiple bond gives the locants as follows:
      • Double bond (C=C) between C-2 and C-3.
      • Triple bond (C≡C) between C-4 and C-5.
    • Combining the locants with the root name "pent" (for 5 carbons) results in the name: Pent-3-en-1-yne.

Therefore, the correct IUPAC name of the compound CH3-CH=CH-C≡CH is Pent-3-en-1-yne.

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