Question
Download Solution PDFUsing tan (A - B) = \(\frac{\tan A-\tan B}{1+\tan A \tan B}\), find the value of tan15°.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven:
tan (A - B) = \(\frac{\tan A-\tan B}{1+\tan A \tan B}\),
Calculation:
Tan15° = Tan ( 45° - 30°)
⇒ \((Tan 45° - Tan 30°)\over 1+ Tan 45° Tan 30°)\)
⇒ \((1 - 1/√3)\over (1 +1/√3)\)
⇒ (√3 - 1) / (√3 + 1) = 2 - \(\sqrt3\)
Last updated on Jul 8, 2025
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