Question
Download Solution PDFValues of dissociation constant, Ka are given as follows.
Acid | Ka |
HCN | 6.2 × 10−10 |
HF | 7.2 × 10−4 |
HNO2 | 4.0 × 10−4 |
Correct order of increasing base strength of the base CN−, F − and \(\rm NO_2^ -\) will be :
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFCONCEPT:
Relationship Between Acid Strength and Conjugate Base Strength
- The strength of a base is inversely related to the strength of its conjugate acid.
- A weaker acid has a stronger conjugate base, and a stronger acid has a weaker conjugate base.
- The dissociation constant (Ka) of an acid can be used to determine the relative strength of its conjugate base.
EXPLANATION:
- Given the dissociation constants (Ka) for the acids:
- HCN: Ka = 6.2 × 10-10
- HF: Ka = 7.2 × 10-4
- HNO2: Ka = 4.0 × 10-4
- The strength of the conjugate bases (CN-, F-, and NO2-) is inversely related to the Ka values of their corresponding acids.
- HCN has the smallest Ka value (6.2 × 10-10), so CN- is the strongest base.
- HNO2 has a Ka value of 4.0 × 10-4, so NO2- is weaker than CN- but stronger than F-.
- HF has the largest Ka value (7.2 × 10-4), so F- is the weakest base.
- Therefore, the correct order of increasing base strength of CN-, F-, and NO2- is:
- F- < NO2- < CN-
Therefore, the correct answer is option 3: F- < NO2- < CN-.
Last updated on Jul 3, 2025
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