Values of dissociation constant, Ka are given as follows.

Acid Ka
HCN 6.2 × 10−10
HF 7.2 × 10−4
HNO2 4.0 × 10−4


Correct order of increasing base strength of the base CN, F − and \(\rm NO_2^ -\) will be : 

This question was previously asked in
VITEEE PYP_125Qs150Min125Marks
View all VITEEE Papers >
  1. \(\mathrm{F}<\mathrm{CN}^{-}<\mathrm{NO}_{2}^{-} \)
  2. \(\mathrm{NO}_{2}^{-}<\mathrm{CN}^{-}<\mathrm{F}^{-} \)
  3. \(\mathrm{F}<\mathrm{NO}_{2}^{-}<\mathrm{CN}^{-} \)
  4. \(\mathrm{NO}_{2}^{-}<\mathrm{F}^{-}<\mathrm{CN}^{-}\)

Answer (Detailed Solution Below)

Option 3 : \(\mathrm{F}<\mathrm{NO}_{2}^{-}<\mathrm{CN}^{-} \)
Free
JEE Main 2025 (Session II) All India Live Test
3.9 K Users
75 Questions 300 Marks 180 Mins

Detailed Solution

Download Solution PDF

CONCEPT:

Relationship Between Acid Strength and Conjugate Base Strength

  • The strength of a base is inversely related to the strength of its conjugate acid.
  • A weaker acid has a stronger conjugate base, and a stronger acid has a weaker conjugate base.
  • The dissociation constant (Ka) of an acid can be used to determine the relative strength of its conjugate base.

EXPLANATION:

  • Given the dissociation constants (Ka) for the acids:
    • HCN: Ka = 6.2 × 10-10
    • HF: Ka = 7.2 × 10-4
    • HNO2: Ka = 4.0 × 10-4
  • The strength of the conjugate bases (CN-, F-, and NO2-) is inversely related to the Ka values of their corresponding acids.
    • HCN has the smallest Ka value (6.2 × 10-10), so CN- is the strongest base.
    • HNO2 has a Ka value of 4.0 × 10-4, so NO2- is weaker than CN- but stronger than F-.
    • HF has the largest Ka value (7.2 × 10-4), so F- is the weakest base.
  • Therefore, the correct order of increasing base strength of CN-, F-, and NO2- is:
    • F- < NO2- < CN-

Therefore, the correct answer is option 3: F- < NO2- < CN-.

Latest VITEEE Updates

Last updated on Jul 3, 2025

->Vellore Institute of Technology will open its application form for 2026 on November 4, 2025.

->The VITEEE 2026 exam is scheduled to be held from April 20, 2026 to April 27, 2026.

->VITEEE exams are conduted for admission to undergraduate engineering programs at the Vellore Institute of Technology (VIT) and its affiliated campus.

->12th pass candidates can apply for the VITEEE exam.

More Equilibrium Questions

Get Free Access Now
Hot Links: teen patti all game teen patti live teen patti vungo