Clock and Calendar MCQ Quiz - Objective Question with Answer for Clock and Calendar - Download Free PDF

Given, 3rd Day of the month = Friday

3 + 18 = 21st day

Friday  + 18 = 21st day

21st day = Tuesday

Now, 

the fourth day after twenty first 

21 + 4 = 25th day

Tuesday + 4 = Saturday

Therefore, 4th day after twenty first will be Saturday.

Hence, option 3 is the correct answer.

Given: Today is Wednesday

So, 59 ÷ 7 = 3 odd day.

Wednesday + 3 = Saturday.

Thus, Today is Wednesday, then after 59 days it will be Saturday.

Hence, "Option 2" is the correct answer.

Given : 10 July 2011 was Sunday.

The number of days from 10 July 2018 to 31 December 2018 :

∴ The number of odd days = 174 ÷ 7 ⇒ 6 

Now, 

Normal year odd days = (+1)

Leap year odd days = (+2)

So, 

The number of odd days in the year 2019 = 191 ÷ 7 ⇒ 2

∴ The total number of odd = 6 + 2 + 2 = 10 ÷ 7 ⇒ 3

So, three odd days get added to Sunday because day asked in future.

∴ Wednesday was the day of the week on the 10 July 2019.

Hence, "Wednesday" is the correct answer.

Given: Today is Thursday

So, number of odd days after 16 days from today = 16 ÷ 7 → 2 odd days.

Day after 16 days from today = Thursday + 2 → Saturday

Therefore, if today is Thursday, the day after 16 days from today will be Saturday.

Hence, "Option 4" is the correct answer.

Given: 25th February, 2008 was a Monday.

Now,

Number of days remaining in February 2008 = 29 - 25 = 4 days (2008 is a leap year).

Number of days in March 2008 until 15th = 15 days.

Total number of days = 4 + 15 = 19 days.

Number of odd days = 19 ÷ 7 = 2 weeks and 5 odd days.

So, the day of 15th March, 2008 will be Monday + 5 days.

Monday + 1 day = Tuesday

Tuesday + 1 day = Wednesday

Wednesday + 1 day = Thursday

Thursday + 1 day = Friday

Friday + 1 day = Saturday

Hence, the day of 15th March, 2008 was Saturday.

Given : Year 2003 = (Leap year + 3)  = 2000 + 3

Explanation : 

In case of a repeating year, we add (11) to the given year :

So, 

2003 + 11 ⇒ 2014

Hence, "2014" is the correct answer.

Additional Information 

•  Trick to remember:

Odd days:
A leap year has 366 days and a non-leap year has 365 days.

Leap year = 366 days or 52 weeks and 2 days. So, here the number of odd days are 2.

Non - Leap year = 365 days or 52 weeks and 1 day. So, here the number of odd days is 1.

Number of odd days in the following years

Total number of odd days in all the years combined = 1+1+1+2 = 5

 8th February 2020  was Saturday

Code for Saturday is 6 and the number of odd days in all the years combined is 5. So, 6 - 5 = 1

1 is the code for Monday.

Hence, 1^st February 2016 was Monday.

Given, at 3 pm

Now at 3.40 pm

In every 5 minutes movement minute hand will make an angle of 30°, thus between 3.30 pm and 3.40 pm it will make an angle of 60° (5 min. + 5 min. = 30° + 30° )

Therefore minute hand is pointing 60° west (9) of the south (6).

Given : Year - 2033

Explanation:

Calculating the odd days for 31st December 2032 :

2032 can be written as → (2000 + 32) so,

2000 → 0

And,

32 → Dividing 32 by 4 will give get quotient 8 i.e:

Now, 40 ÷ 7 = Remainder = 5

As 5 is the code for Friday , thus it is Friday on 31st December 2032.

And, 

1st January is one day after 31st December 2032, so it will be Saturday.

Hence, "Saturday" is the correct answer.

 Additional Information

1. Ordinary year (365 days) = 1 odd day
2. Leap year (366 days) = 2 odd days

• Number of odd days for the days of week.

• Number of odd days for the days of months.

• Number of odd days for the years.

Note - Any multiple year of 400 like 800, 1200,1600, 2000 etc will have '0' Odd days.

Given: 11th August 2004 = Friday.

Now,

Total days between 11th August 2004 to 11th February 2006

= 20(Aug) + 30(Sept) + 31(Oct) + 30(Nov) + 31(Dec) + 365(2005) + 31(Jan) + 11(Feb) = 549 days.

And, 549/7 = 78 week and 3 odd days.

So, 11th February 2006 = Friday + 3 = Monday.

Hence, the correct answer is "Monday".

Consider, 

Monday= 1

Tuesday = 2

Wednsday = 3

Thursday = 4

Friday = 5 

Saturday = 6

Sunday = 7

As 2000 is divisible by 400 the number of odd days is 0.

Number of leap years till 2016 = 4 (2004, 2008, 2012 and 2016)

Number of ordinary years till 2016 = 12

Number of odd days till 2016 = 12 + (4 × 2) = 20 odd days

Number of odd days in January, 2017 = 3

Number of odd days in February, 2017 = 0

Total number of odd days till 8^th March 2017 = 20 + 3 + 8 = 31 odd days = 3 odd days

Odd days:

A non-leap year has 365 days and a leap year has 366 days.

Non-leap year = 365 days or 52 weeks and 1 day. So, here the number of odd days is 1.

Leap year = 366 days or 52 weeks and 2 days So, here the number of odd days are 2.

Leap year between 2000 to 2012 = 2004, 2008 and 2012

And,

The non-leap year between 2000 and 2012 = 2001, 2002, 2003, 2005, 2006, 2007, 2009, 2010 and 2011

So, total number of odd day between 2000 and 2012 = 9 (Total Non- leap year) + 2 + 2 + 2 = 15 days = 1 odd day

19 July 2000 was a Wednesday

=> Day on 19 July 2012 = Wednesday + 15

= Wednesday + remainder of 15/7

= Wednesday + 1 (odd day) = Thursday

Therefore, 19 July 2012 = Thursday

Now,

15 June 2012 = 19 July 2012 – 34 days

= Thursday – 34

= Thursday – the remainder of 34/7

= Thursday – 6 (In reverse direction)

= Friday

Hence, 15 June 2012 was “Friday”.

At 3:30 p.m., the minute hand of a clock points towards East.

similarly,

The hour hand at 9:00 p.m. will point towards South.

Hence, 'South' is the correct answer.

Total no. of years difference between 2010 – 2018 = 8

Number of leap years till 2018 = 2 (2012 and 2016)

Number of ordinary years till 2018 = 6

Number of odd days till 2018 = 6 + (2 × 2) = 6 + 4 = 10 odd days

Total number of odd days till 1^st January 2018 = 10 odd days = 3 odd days

So, we have move 3 days backward from Monday i.e., Friday.

The pattern followed here is:

The total number of odd days is listed below:

Therefore 2015 will be the repeated calendar of 2009.Shortcut Trick

So, 2008 + 1 = 2009 + 6 = 2015

So, 2015 is the same as the calendar for the year 2009

Hence, the correct answer is "2015".