A can paint a painting in 12 days. B can paint the same in 8 days. C can paint the same in 10 days. Find the (approximate) number of days in which the painting can be painted by A if he is accompanied by both B and C together on alternate days and A starts painting on the first day alone. 

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  1. 4.4 days
  2. 5.4 days
  3. 7.2 days
  4. 8.5 days

Answer (Detailed Solution Below)

Option 2 : 5.4 days
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Detailed Solution

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Given:

A can paint a painting in 12 days.

B can paint the same in 8 days.

C can paint the same in 10 days.

Concept Used:

Work = Time × Efficiency

Calculation:

Total work = LCM(12, 8, 10) = 120

Efficiency of A = 120/12 = 10

Efficiency of B = 120/8 = 15

Efficiency of C = 120/10 = 12

According to question,

A if he is accompanied by both B and C together on alternate days. A start alone on first day.

Work completed in 2 days = 47

Work completed in 4 days = 47 × 2 = 94

Work completed in 5 days = 94 + 10 = 104

Remaining work = 16

Time to complete 16 units of work by three of them = 16/37 = 0.4 days

Total number of days required to complete the work = 5 + 0.4 = 5.4 days

Option 2 is the correct answer.

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