A hemispherical tank full of water is emptied by a pipe at the rate of 7.7 litres per second. How much time (in hours) will it take to empty part of the tank, if the internal radius of the tank is 10.5 m?

Question

Question

This question was previously asked in

SSC CGL Tier 2 Quant Previous Paper 2 (Held On: 16 November 2020)

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Answer 1

Given:

The internal radius of the tank is 10.5 m

A pipe at the rate of 7.7 liters per second emptied the tank.

Concept:

Volume of hemisphere = 2π/3 × r³

1 m³ = 1000 L

1000 cm³ = 1 L

Calculation:

The volume of the hemispherical tank is

⇒ 2/3 × 22/7 × 10.5 × 10.5 × 10.5

⇒ 2425.5 m³

The capacity of the tank is

⇒ 2425.5 × 1000 L

⇒ 2425500 L

So,

Time taken by the pipe emptied 2/3 part of the tank is

⇒ (2/3 × 2425500) ÷ 7.7 sec

⇒ 210,000 sec

Time in hours

⇒ 210,000/3600

⇒ 175/3 hours

∴ The required time is 175/3 hours.

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