A solenoid has a core of material with relative permeability 500 and its windings carry a current of 1 A. The number of turns of the solenoid is 500 per meter. The magnetization of the material is nearly

  1. 2.5 × 103 A m-1
  2. 2.5 × 105 A m-1
  3. 2.0 × 103 A m-1
  4. 2.0 × 105 A m-1

Answer (Detailed Solution Below)

Option 2 : 2.5 × 105 A m-1
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Concept:

Magnetic susceptibility is a dimensionless proportionality constant that indicates the degree of magnetization of a material in response to an applied magnetic field, represented by the symbol “χ”

Magnetic Permeability expresses the total magnetization of material it is represented by “µ”

These two are related by the formula µ = µ0(1 + χ)

Also, µ = µr µo

µr is relative permeability it shows how much more permeable magnetic material is compared to air

µ0 = permeability of air = 4 π × 10-7

Calculation:

Here, n = 500 turns/m

I = 1 A, μr = 500

Magnetic intensity, H = nI = 500 m-1 × 1 A

= 500 A m-1

As μr = 1 + χ

Where χ is the magnetic susceptibility of the material or χ = (μr – 1)

Magnetisation, M = χH

= (μr – 1) H

= (500 - 1) × 500 A m-1

= 499 × 500 A m-1

= 2.495 × 105 A m-1

≈ 2.5 × 105 A m-1
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