Question
Download Solution PDFAn oil of specific gravity 0.9 contained in a vessel. At a point the height of oil is 40 m and for the density of water = 1000 kg/m3, the corresponding height of water at the point will be
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
Hydrostatic pressure of fluid is given by,
P = ρgh
Where, ρ = Density of fluid, g = Acceleration due to gravity and h = height of water surface
Calculation:
Given, Specific gravity of oil = 0.9
Density of oil, ρ = 0.9 × density of water = 0.9 × 1000 = 900 kg/m3
This is solved by using Pascal’s Law, which states that pressure at all the points in a horizontal direction will be same.
Pressure due to oil height = pressure due water height
\(\begin{array}{l} {\left( {ρ gh} \right)_{oil}} = {\left( {ρ gh} \right)_{water}}\\ 900 \times 9.81 \times 40 = 1000 \times 9.81 \times h \end{array}\)
∴ h = 36 m of water columnLast updated on May 28, 2025
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