Question
Download Solution PDFযদি \(\rm 7a - {7\over a} + 4 = 0\) হয়, তাহলে \(\rm a^3 - {1 \over a^3} - 1\) এর মান নির্ণয় করো।
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFপ্রদত্ত:
7a - (7/a) = - 4
ব্যবহৃত সূত্র:
যদি a + (1/a) = P হয়
⇒ a3 - (1/a3) = P3 + 3P
গণনা:
7a - (7/a) = - 4
⇒ a - (1/a) = (- 4/7)
⇒ a3 - (1/a3) = (- 4/7)3 + 3 x (- 4/7)
⇒ (- 64/343) - 12/7
⇒ (- 64 - 588)/343
⇒ a3 - (1/a3) = (- 652/343)
a3 - (1/a3) - 1
⇒ - 652/343 - 1
⇒ (- 652 - 343)/343
⇒ - 995/343
∴ সঠিক উত্তর হল (- 995/343)
Last updated on Jul 9, 2025
-> The SSC CGL Notification 2025 for the Combined Graduate Level Examination has been officially released on the SSC's new portal – www.ssc.gov.in.
-> Bihar Police Admit Card 2025 Out at csbc.bihar.gov.in
-> This year, the Staff Selection Commission (SSC) has announced approximately 14,582 vacancies for various Group B and C posts across government departments.
-> The SSC CGL Tier 1 exam is scheduled to take place from 13th to 30th August 2025.
-> Aspirants should visit ssc.gov.in 2025 regularly for updates and ensure timely submission of the CGL exam form.
-> Candidates can refer to the CGL syllabus for a better understanding of the exam structure and pattern.
-> The CGL Eligibility is a bachelor’s degree in any discipline.
-> Candidates selected through the SSC CGL exam will receive an attractive salary. Learn more about the SSC CGL Salary Structure.
-> Attempt SSC CGL Free English Mock Test and SSC CGL Current Affairs Mock Test.
-> The AP DSC Answer Key 2025 has been released on its official website.
-> The UP ECCE Educator 2025 Notification has been released for 8800 Posts.