Question
Download Solution PDFनिम्न तालिका से माध्य की गणना कीजिए।
|
स्कोर |
बारंबारता |
|
0-10 |
2 |
|
10-20 |
4 |
|
20-30 |
12 |
|
30-40 |
21 |
|
40-50 |
6 |
|
50-60 |
3 |
|
60-70 |
2 |
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिया गया है:
|
स्कोर |
बारंबारता |
|
0-10 |
2 |
|
10-20 |
4 |
|
20-30 |
12 |
|
30-40 |
21 |
|
40-50 |
6 |
|
50-60 |
3 |
|
60-70 |
2 |
प्रयुक्त सूत्र:
माध्य = \(\Sigma fixi \over \Sigma fi\)
जहां fi = विशेष मान की बारंबारता
xi = आवृत्ति वर्ग का मध्य मान
गणना:
| स्कोर | बारंबारता (fi) | xi | fixi |
| 0-10 | 2 | 5 | 10 |
| 10-20 | 4 | 15 | 60 |
| 20-30 | 12 | 25 | 300 |
| 30-40 | 21 | 35 | 735 |
| 40-50 | 6 | 45 | 270 |
| 50-60 | 3 | 55 | 165 |
| 60-70 | 2 | 65 | 130 |
| Total (∑): | 50 | 245 | 1670 |
माध्य = \(1670 \over 50\) = 33.4
∴ दी गई बारंबारता बंटन सारणी का माध्य 33.4 है।
Last updated on Jun 13, 2025
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