Question
Download Solution PDFनिम्नलिखित भौतिक राशियों में से कौन-सी राशि आयाम MLT-2A-2 से संबंधित है?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFसंकल्पना:
चुम्बकीय पारगम्यता एक अनुपातिक स्थिरांक है।
\(B \propto H\)
जहाँ B = चुम्बकीय तीव्रता, H = चुम्बकत्व तीव्रता
\(B = μ H\)
μ उस स्थान की चुम्बकीय पारगम्यता है,
चुम्बकीय पारगम्यता के आयाम की गणना करने पर
\(μ = \frac{B}{H}\)= \(\frac{N/Am}{A/m}\) = \(\frac{N}{A^2}\) = \(\frac{[MLT^{-2}]}{[A^2]}\)
μ = [MLT-2A-2]
Additional Information
- चुम्बकीय क्षेत्र के लिए आयामी सूत्र B = [ML0T-2A-1]
- मरोड़ स्थिरांक के लिए आयामी सूत्र G = [ML2T-2]
- चुम्बकीय आघूर्ण के लिए आयामी सूत्र = [M0L2T0A]
Last updated on Jun 19, 2025
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