Question
Download Solution PDFIf the number of bellows elements is made double and the thickness of the bellows element is made half, the displacement of the element for the same applied pressure would be the _______.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
A metallic bellow is a series of circular parts, resembling the folds in an accordion. These parts are formed or joined in such a manner that they expanded or contracted axially.
The displacement of the bellows element is given by
\(d=\frac{0.453~Pbn{{D}^{2}}\sqrt{1-{{\nu }^{2}}}}{E{{t}^{3}}}\)
Where P = pressure in N/m2
b = radius of each corrugation
n = thickness of the wall in m
D = mean diameter, m
E = modulus of elasticity, N/m2
ν = Poisson’s ration
Calculation:
\(d\propto \frac{n}{{{t}^{3}}}\)
n made double and t made half, hence displacement becomes 16 times.Last updated on Jun 16, 2025
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