Question
Download Solution PDFIn the given figure, diameter AB and chord CD of a circle meet at P. PT is a tangent to the circle at T. If CD = 8 cm, PD = 10 cm and PB = 8 cm, find AB.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
Secant Property
If chord AB and chord CD of a circle intersect at a point P, then
PA × PB = PC × PD
Calculation:
Let the AB = x
PA × PB = PC × PD
⇒ (8 + x) × 8 = 18 × 10
⇒ (8 + x) = 180/8
⇒ (8 + x) = 22.5
⇒ x = 22.5 - 8
= 14.5
∴ The answer is 14.5.
Last updated on Jun 13, 2025
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