Question
Download Solution PDF14 सेमी व्यास आणि 24 सेमी उंचीचा एक शंकू 14 सेमी बाजूच्या घनाच्या वर ठेवला आहे. तर संपूर्ण आकृतीचे पृष्ठफळ शोधा.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFतिरकस उंची = √(उंची2 + त्रिज्या2 ) = √(242 + 72 ) = 25
शंकूचे वक्रपृष्ठफळ = π × त्रिज्या × तिरकस उंची = (22/7) × 7 × 25 = 550 चौ.सेमी
घनाचे पृष्ठफळ = 6 × बाजू2 = 6 × (14)2 = 1176 चौ.सेमी
परंतु शंकूच्या पायाने व्यापलेले काही क्षेत्रफळ = π × त्रिज्या2
⇒ (22/7) × 72 = 154 सेमी2
⇒ एकूण पृष्ठफळ = 550 + 1176 - 154 = 1,572 चौ.सेमी
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