Question
Download Solution PDF10 सेमी बाजू असलेल्या चौकोनी शंकूचा आकार 400 सेमी3 आहे. शंकूच्या एकूण पृष्ठभागाचे क्षेत्रफळ शोधा.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFशंकूच्या पायाचे क्षेत्रफळ = चौरसाचे क्षेत्रफळ = (10)2 = 100 सेमी2
∵ शंकूचे घनफळ = 1/3 × पाया क्षेत्र × उंची
⇒ 400 = 1/3 × 100 × उंची
⇒ शंकूची उंची = 12 सेमी
आता,
⇒ शंकूची तिरकी उंची = √[(उंची)2 + (बाजू/2)2] = √(144 + 25) = √169 = 13 सेमी
⇒ त्रिकोणी पृष्ठभागाचे क्षेत्रफळ = 1/2 × बाजू × तिरकी उंची = 1/2 × 10 × 13 = 65 सेमी2
∵ चौकोनी शंकूला चार त्रिकोणी पृष्ठ आणि एक चौकोनी पाया असतो,
∴ शंकूचे एकूण पृष्ठभाग क्षेत्रफळ = 4(65) + 100 = 360 सेमी2
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