Question
Download Solution PDFPQRS हा एक चक्रीय समलंब चौकोन आहे जेथे PQ हा SR ला समांतर आहे आणि PQ हा व्यास आहे. जर ∠QPR = 40° असेल तर ∠PSR = ?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिलेले आहे:
PQRS हा एक चक्रीय समलंब आहे जेथे PQ हा RS ला समांतर आहे.
PQ हा व्यास आहे आणि ∠QPR = 40° आहे.
संकल्पना:
अर्धवर्तुळात बनवलेला कोन काटकोन असतो.
चक्रीय समलंब चौकोनाच्या विरुद्ध कोनांची बेरीज 180° असते.
गणना:
त्रिकोण PQR मध्ये,
∠RPQ + ∠RQP + ∠QRP = 180° [त्रिकोणांच्या कोनांच्या बेरजेचा गुणधर्म]
⇒ 40° + ∠RQP + 90° = 180°
⇒ ∠RQP = 180° - 130° = 50°
∠RQP + ∠PSR = 180° [पूरक कोन]
∴ ∠PSR = 180° - 50° = 130°
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