Question
Download Solution PDFशंकू आकाराच्या साठवण टाकीची उंची आणि त्रिज्या अनुक्रमे 9 फूट आणि 7 फूट आहे. टाकीत किती पाणी साठवता येईल ते काढा? (\(\pi\)=(22)/(7) वापरा)
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिलेल्याप्रमाणे:
उंची (h) = 9 फूट.
त्रिज्या (r) = 7 फूट.
वापरलेले सूत्र:
शंकूचे घनफळ (V) = (1/3) × π × r2 × h
गणना:
V = (1/3) × (22/7) × 72 × 9
⇒ V = (1/3) × (22/7) × 49 × 9
⇒ V = (1/3) × 22 × 7 × 9
⇒ V = (1/3) × 1386
⇒ V = 462 घन फूट.
∴ योग्य उत्तर पर्याय (2) आहे.
Last updated on Jun 17, 2025
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