समांतरभुज चौकोनाच्या दोन बाजूंची लांबी 3 सेमी आणि 10 सेमी आहे. समांतरभुज चौकोनाच्या कर्णांच्या वर्गांची बेरीज किती आहे?

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SSC CGL Tier 2 Quant Previous Paper 1 (Held On: 15 November 2020)
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  1. 218 चौरस सेमी
  2. 109 चौरस सेमी
  3. 169 चौरस सेमी
  4. 206 चौरस सेमी

Answer (Detailed Solution Below)

Option 1 : 218 चौरस सेमी
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Detailed Solution

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दिलेल्याप्रमाणे:

समांतरभुज चौकोनाची पहिली बाजू = 3 सेमी

समांतरभुज चौकोनाची दुसरी बाजू = 10 सेमी

वापरलेली संकल्पना:

समांतरभुज चौकोनाच्या कर्णांच्या वर्गांची बेरीज त्याच्या बाजूंच्या वर्गांच्या बेरजेसमान असते

गणना:

समजा समांतरभुज चौकोन ABCD आहे,

AB = 3 सेमी

BC = 10 सेमी

CD = 3 सेमी

DA = 10 सेमी

संकल्पना वापरून,

कर्णांच्या वर्गांची बेरीज = (AB2 + BC2 + CD2 + DA2)

⇒ (32 + 102 + 32 + 102)

⇒ (9 + 100 + 9 + 100)

⇒ 218

∴ समांतरभुज चौकोनाच्या कर्णांच्या वर्गांची बेरीज 218 चौरस सेमी आहे

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-> The SSC CGL Notification 2025 has been released on 9th June 2025 on the official website at ssc.gov.in.

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