Question
Download Solution PDFThe mass of a single-degree damped vibrating system is 7.5 kg and it makes 24 free oscillation in 14 s when disturbed from its equilibrium position. The amplitude of vibration reduces to 0.25 of its initial value after five oscillations. Then the logarithmic decrement will be
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
Logarithmic decrement is the log of successive decrement ratio:
Logarithmic decrement
\(\delta =\ln\left| {\frac{{{X_{n}}}}{{{X_{n+1 }}}}} \right|= \frac{1}{n}\ln\left| {\frac{{{X_{1}}}}{{{X_{n+1 }}}}} \right|\)
Where n is the number of oscillations made to reduce the amplitude from X1 to X(n+1)
Calculation:
Given X5 = 0.25 X0
\(\frac{{{X_5}}}{{{X_0}}} = 0.25\;\)
\(\frac{{{X_5}}}{{{X_0}}} = \frac{X_5}{X_4}\times\frac{X_4}{X_3}\times\frac{X_3}{X_2}\times\frac{X_2}{X_1}\times\frac{X_1}{X_0}\)
Logarithmic decrement
\(\delta = \frac{1}{5}\ln\left| {\frac{{{X_0}}}{{{X_5}}}} \right|\)
\(\delta = \frac{1}{5}\ln\left| 4 \right|\)
Last updated on May 28, 2025
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