The secondary unbalanced forces of reciprocating masses in the engine is

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HPCL Engineer Mechanical 12 Aug 2021 Official Paper (Shift 2)
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  1. Inversely proportional to the ratio of the length of connecting rod to crank radius
  2. Proportional to the ratio of the length of connecting rod to crank radius
  3. Inversely proportional to crank radius
  4. Proportional to the length of connecting rod

Answer (Detailed Solution Below)

Option 1 : Inversely proportional to the ratio of the length of connecting rod to crank radius
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Detailed Solution

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Explanation:

SSC JE ME 12

The unbalanced force due to reciprocating masses varies in magnitude but is constant in direction while due to the revolving masses, the unbalanced force is constant in magnitude but varies in direction.

Unbalanced force:

\({F_U}= m{ω ^2}R\left( {\cosθ + \frac{{\cos2θ }}{n}} \right) \)

\(F_U= m{ω ^2}R\cosθ + m{ω ^2}R \times \frac{{\cos2θ }}{n}\)

\(F_P=m{ω ^2}R\cosθ\) = Primary unbalance force.

\(F_S=m{ω ^2}R \times \frac{{\cos2θ }}{n}\) = Secondary unbalance force.

where n = ratio of the length of connecting rod to crank radius.

Thus from the expression of secondary force, \(F_S=m{ω ^2}R \times \frac{{\cos2θ }}{n}\), we can see that Fs is inversely proportional to n (ratio of the length of connecting rod to crank radius).

 

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