Question
Download Solution PDFThermal decomposition of a Mn compound (X) at 513 K results in compound Y, MnO2 and gaseous product MnO2 reacts with NaCl and concentrated H2SO4 to give a pungent gas Z, X, Y and Z, respectively, are:
Answer (Detailed Solution Below)
Detailed Solution
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The thermal decomposition of potassium permanganate produces potassium manganate, manganese (IV) oxide, and oxygen.
\(2{\rm{KMn}}{{\rm{O}}_4}{\rm{\;}}\left( {\rm{X}} \right)\mathop \to \limits^{513{\rm{\;K}}} {{\rm{K}}_2}{\rm{Mn}}{{\rm{O}}_4}{\rm{\;}}\left( {\rm{Y}} \right) + {\rm{Mn}}{{\rm{O}}_2} + {{\rm{O}}_2}{\rm{\;}}\left( {{\rm{gas}}} \right)\)
\({\rm{Mn}}{{\rm{O}}_2} + {\rm{NaCl}} + {{\rm{H}}_2}{\rm{S}}{{\rm{O}}_4} \to {\rm{MnS}}{{\rm{O}}_4} + {\rm{C}}{{\rm{l}}_2}{\rm{\;}}\left( {\rm{Z}} \right) + {\rm{N}}{{\rm{a}}_2}{\rm{S}}{{\rm{O}}_4} + {{\rm{H}}_2}{\rm{O}}\)
The thermal decomposition of an ‘Mn’ compound (X) is KMnO4 (potassium permanganate) at 513 K results in compound Y, K2MnO4 is (Potassium manganate) along with MnO2 (manganese (IV) oxide) and gaseous product. Here the MnO2 reacts with NaCl (sodium chloride) and concentrated H2 SO4 (sulfuric acid) to give a pungent gas Z is Cl2 (chlorine).
X = KMnO4
Y = K2MnO4
Z = Cl2Last updated on May 23, 2025
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