Two workers - Sagar and Manish - are working on a heavy machine to melt waste metal. Sagar can complete the work in 15 days while both workers on alternate basis can complete the work in 12 days. In how many days can Manish alone complete the work?

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SSC Selection Post 2024 (Matriculation Level) Official Paper (Held On: 25 Jun, 2024 Shift 1)
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  1. 10
  2. 30
  3. 9
  4. 18

Answer (Detailed Solution Below)

Option 1 : 10
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Detailed Solution

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Given:

Sagar's time to complete the work alone = 15 days

Sagar and Manish on alternate basis complete the work in 12 days

Formula used:

Let Manish's time to complete the work alone = M days

Work done by Sagar in 1 day = 1/15

Work done by Manish in 1 day = 1/M

Total work = 1

In 12 days, Sagar works for 6 days and Manish works for 6 days (since they work on alternate days)

Total work done in 12 days = 6 × (1/15) + 6 × (1/M) = 1

Calculation:

6/15 + 6/M = 1

⇒ 2/5 + 6/M = 1

⇒ 6/M = 1 - 2/5

⇒ 6/M = 3/5

⇒ M = 6 × 5/3

⇒ M = 10

∴ The correct answer is option 1.

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