Veena and Karmesh were at different places in Delhi. They fixed a meeting point to meet to settle some issue. Veena started her journey at 8:00 a.m. from place A and reached place B at 4:00 p.m. and Karmesh started moving from place B 2 hours later than the time Veena started and could reach place A at 5:00 p.m. the same day, via the same route. At what time will Karmesh and Veena meet each other?

Question

Question

This question was previously asked in

SSC Selection Post 2024 (Higher Secondary Level) Official Paper (Held On: 21 Jun, 2024 Shift 2)

Answer 1

Given:

Veena started from place A at 8:00 a.m. and reached place B at 4:00 p.m.

Karmesh started from place B at 10:00 a.m. and reached place A at 5:00 p.m.

Formula Used:

Meeting time calculation using relative speed concept.

Calculation:

Veena's total travel time = 4:00 p.m. - 8:00 a.m. = 8 hours

Karmesh's total travel time = 5:00 p.m. - 10:00 a.m. = 7 hours

Let the distance between A and B be D.

Veena's speed = D / 8

Karmesh's speed = D / 7

Relative speed of Veena and Karmesh = (D/8) + (D/7)

Relative speed = \( \frac{D}{8} + \frac{D}{7} = \frac{7D + 8D}{56} = \frac{15D}{56} \)

Since, Veena started her journey at 8:00 AM and Karmesh started his journey at 10: 00 AM.

So, distance travelled by Veena in 2 hours = 2 × D/8 = D/4

Thus, Remaining distance = D - D/4 = 3D/4

Now,

Time is taken to meet after 10 PM

⇒ Remaining distance / Relative speed

⇒ (3D/4)/ (15D/56)

⇒ 3D/4 × 56/15D

⇒ 14/5 hours = 2 hours 48 minutes

So Meeting time = 10:00 a.m. + 2 hours 48 minutes = 12:48 PM

The correct answer is option (2).

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