Which two signs and two numbers should be interchanged in the following equation to make it correct?

10 × 11 + 19 - 323 ÷ 3 = 50

This question was previously asked in
SSC CGL 2022 Tier-I Official Paper (Held On : 12 Dec 2022 Shift 3)
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  1. 10 and 19, - and +
  2. 3 and 19, - and ×
  3. 10 and 11, - and ÷
  4. 10 and 323, + and ÷

Answer (Detailed Solution Below)

Option 2 : 3 and 19, - and ×
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Detailed Solution

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The pattern followed here is:

We have to interchange the signs and two numbers in the following equations to make it correct.

Let's check each option one by one.

Option 1) 10 and 19, - and +

Given: 10 × 11 + 19 - 323 ÷ 3 = 50

After interchanging the sign and two numbers we get the;

⇒ 19 × 11 - 10 + 323 ÷ 3 = 50

19 × 11 - 10 + 107.66 = 50

209 - 10 + 107.66 = 50

⇒ 316.6 - 10 = 50

⇒ 306.6 ≠ 50 

⇒ LHS ≠ RHS

Option 2) 3 and 19, - and ×

Given: 10 × 11 + 19 - 323 ÷ 3 = 50

After interchanging the sign and two numbers we get the;

⇒ 10 - 11 + 3 × 323 ÷ 19 = 50

⇒ 10 - 11 + 3 × 17 = 50

10 - 11 + 51 = 50

61 - 11 = 50

⇒ 50 = 50

⇒ LHS = RHS

Option 3) 10 and 11, - and ÷

Given: 10 × 11 + 19 - 323 ÷ 3 = 50

After interchanging the sign and two numbers we get the;

⇒ 11 × 10 + 19 ÷ 323 - 3 = 50

11 × 10 + 0.0588 - 3 = 50

110 + 0.0588 - 3 = 50

110.0588 - 3 = 50

⇒107.0588 ≠ 50

⇒ LHS ≠ RHS

Option 4) 10 and 323, + and ÷

Given: 10 × 11 + 19 - 323 ÷ 3 = 50

After interchanging the sign and two numbers we get the;

⇒ 323 × 11 ÷ 19 - 10 + 3 = 50

323 × 0.578 - 10 + 3 = 50

187 - 10 + 3 = 50

⇒ 190 - 10 = 50

⇒ 180 ≠ 50

⇒ LHS ≠ RHS

Hence, the correct answer is "Option 2".

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