Question
Download Solution PDFA voltage e(t) = 200 sin 1000 t is applied across a series RLC circuit, where R = 40 Ω, L = 0.13 H and C = 10 μF. What is the value of the total impedance of the circuit?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept
The impedance of a series RLC circuit is given by:
\(Z=\sqrt{R^2+(ω L-{1\over ω C})^2}\)
where, ω = Frequency in rad/s
R = Resistance
L = Inductance
C = Capacitance
Calculation
Given, R = 40 Ω, L = 0.13 H and C = 10 μF
ω = 1000 rad/s
\(Z=\sqrt{(40)^2+(1000\times 0.13 -{1\over 1000 \times 10\times 10^{-6}})^2}\)
Z = 50 Ω
Last updated on Jun 16, 2025
-> SSC JE Electrical 2025 Notification will be released on June 30 for the post of Junior Engineer Electrical/ Electrical & Mechanical.
-> Applicants can fill out the SSC JE application form 2025 for Electrical Engineering from June 30 to July 21.
-> SSC JE EE 2025 paper 1 exam will be conducted from October 27 to 31.
-> Candidates with a degree/diploma in engineering are eligible for this post.
-> The selection process includes Paper I and Paper II online exams, followed by document verification.
-> Prepare for the exam using SSC JE EE Previous Year Papers.