दिए गए चित्र में, PAB एक छेदक है और PT, P से वृत्त की एक स्पर्श रेखा है। यदि PT = 8 सेमी, PA = 6 सेमी और AB = x सेमी है, तो x का मान क्या है?

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SSC CGL 2023 Tier-I Official Paper (Held On: 14 Jul 2023 Shift 1)
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  1. \(\frac{14}{9}\)
  2. \(\frac{1}{3}\)
  3. \(\frac{14}{3}\)
  4. \(\frac{4}{3}\)

Answer (Detailed Solution Below)

Option 3 : \(\frac{14}{3}\)
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Detailed Solution

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दिया गया है:

PT = 8 सेमी 

PA = 6 सेमी

प्रयुक्त सूत्र

PT2 = PA × PB

यहाँ, PT स्पर्शरेखा है

गणना:

qImage660a21425b88bbe1b8a27b97

माना AB "x" है

PT2 = PA × PB

82 = 6(6 + x)

32/3 = 6 + x

x = 14/3

AB का मान 14/3 सेमी है।

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