सरल कीजिए: √6(4096) + √4(50625) + ∛(21952) + √(3364)

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RRB NTPC Graduate Level CBT-I Official Paper (Held On: 06 Jun, 2025 Shift 2)
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  1. 105
  2. 55
  3. 24
  4. 75

Answer (Detailed Solution Below)

Option 1 : 105
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दिया गया है:

सरल कीजिए: √6(4096) + √4(50625) + ∛(21952) + √(3364)

प्रयुक्त सूत्र:

nवें मूल के लिए: √n(x) = x1/n

गणना:

चरण 1: प्रत्येक पद का मान ज्ञात कीजिए

⇒ √6(4096) = 40961/6 = 4

⇒ √4(50625) = 506251/4 = 15

⇒ ∛(21952) = 219521/3 = 28

⇒ √(3364) = 33641/2 = 58

चरण 2: परिणामों को जोड़ें

⇒ 4 + 15 + 28 + 58 = 105

∴ सही उत्तर विकल्प (1) है।

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