Question
Download Solution PDFగోళం యొక్క పరిమాణం అర్ధగోళం యొక్క పరిమాణంకు సమానం. వాటి వ్యాసార్థం యొక్క నిష్పత్తిని కనుగొనండి.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFఫార్ములా:
గోళం యొక్క పరిమాణం = [4/3] × πr3
అర్ధగోళం యొక్క పరిమాణం = [2/3] × πr3
లెక్కింపు:
గోళం మరియు అర్ధగోళం యొక్క వ్యాసార్థం వరుసగా R మరియు r గా ఉండనివ్వండి
ప్రశ్న ప్రకారం
[4/3] × π × R3 = [2/3] × π × r3
⇒ R3/r3 = 1/2
⇒ R : r = 1 : ∛2
Last updated on Jun 13, 2025
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