Question
Download Solution PDFIf the peak value of an alternating current is 8 A, then the RMS value of the current will be ________.
This question was previously asked in
SSC JE Electrical 10 Oct 2023 Shift 2 Official Paper-I
Answer (Detailed Solution Below)
Option 3 : 4√2 A
Free Tests
View all Free tests >
RRB JE CBT I Full Test - 23
14.2 K Users
100 Questions
100 Marks
90 Mins
Detailed Solution
Download Solution PDFConcept:
- An alternating current is an electric current that reverses direction periodically
- The general equation is given by
- I = i0 sin (ωt)
- I = i0 cos (ωt)
- RMS means Root-Mean-Square of instantaneous current
- \(I_{rms} = \frac{I_0}{√2}\)
- I0 = Peak current, ω = frequency
Calculation:
Given, I0 = Peak current = 8 A
\(I_{rms} = \frac{I_0}{√2}\)
= \(\frac{8}{\sqrt2} =4\sqrt2\)
Last updated on Jun 16, 2025
-> SSC JE Electrical 2025 Notification will be released on June 30 for the post of Junior Engineer Electrical/ Electrical & Mechanical.
-> Applicants can fill out the SSC JE application form 2025 for Electrical Engineering from June 30 to July 21.
-> SSC JE EE 2025 paper 1 exam will be conducted from October 27 to 31.
-> Candidates with a degree/diploma in engineering are eligible for this post.
-> The selection process includes Paper I and Paper II online exams, followed by document verification.
-> Prepare for the exam using SSC JE EE Previous Year Papers.