Question
Download Solution PDFसमांतरभुज चौकोनामध्ये ABCD, AL आणि CM अनुक्रमे CD आणि AD ला लंब आहेत. AL = 20 सेमी, CD = 18 सेमी आणि CM = 15 सेमी. समांतरभुज चौकोनाची परिमिती किती आहे?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिलेल्याप्रमाणे:
समांतरभुज चौकोनात ABCD, AL आणि CM अनुक्रमे CD आणि AD वर लंब आहेत.
AL = 20 सेमी, CD = 18 सेमी आणि CM = 15 सेमी
वापरलेले सूत्र:
समांतरभुज चौकोनाचे क्षेत्रफळ = पाया × उंची
समांतरभुज चौकोनाची परिमिती = 2 × (समांतर बाजूंची बेरीज)
गणना:
पाया DC = AL × DC = 20 × 18 सह ABCD चे क्षेत्रफळ
⇒ 360 सेमी2
पुन्हा, पाया AD = CM × AD = 18 × AD सह ABCD चे क्षेत्रफळ
⇒ 360 सेमी2 = 15 × AD
⇒ AD = 24 सेमी
∴ AD = BC = 24 सेमी, DC = AB = 18 सेमी
ABCD ची परिमिती = 2 × (24 + 18)
⇒ 2 × 42
⇒ 84 सेमी
∴ आवश्यक परिणाम = 84 सेमी
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