Question
Download Solution PDFP, Q and R can complete a piece of work in 10 days, 15 days and 20 days, respectively. If they work together, in how many days can they finish the same work?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven:
A can do the work in 10 days
B can do the work in 15 days
C can do the work in 20 days
Formula used:
Work done = Time taken × Efficiency
Time taken ∝ 1/Efficiency
Calculation:
1st day work by A = 1/10
2nd day work by B = 1/15
3rd day work by C = 1/30
Total work completed in 3 days
⇒ 1/10 + 1/15 + 1/20
⇒ (6 + 4 + 3)/60 = 13/60
Time taken to complete the work
⇒ 60/13
⇒ 4(8/13)
They finish the same work in 4(8/13) days.
Time |
Total work (LCM of time) |
Efficiency |
|
A |
10 |
6 |
|
B |
15 |
60 |
4 |
C |
20 |
3 |
Work done together in 1 day is:
⇒ 6 + 4 + 3 = 13
Total time required to complete the work ⇒ 60/13
⇒ \(4\frac{8}{13}\) days
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