ΔABC में, MN∥BC, चतुर्भुज MBCN का क्षेत्रफल = 130 सेमी2। यदि AN : NC = 4 : 5, तो ΔMAN का क्षेत्रफल है:

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SSC CGL Previous Paper 65 (Held On: 3 March 2020 Shift 1)
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  1. 45 सेमी2
  2. 65 सेमी2
  3. 40 सेमी2
  4. 32 सेमी2

Answer (Detailed Solution Below)

Option 4 : 32 सेमी2
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F1 A.K 13.5.20 Pallavi D1

दिया गया है,

चतुर्भुज MBCN का क्षेत्रफल = 130 सेमी2.

AN : NC = 4 : 5

अतः, AC = 4 + 5 = 9

ΔABC में, यदि MN∥BC, तो

ΔAMN का क्षेत्रफल/ΔABC का क्षेत्रफल = (AN/AC)2

ΔAMN का क्षेत्रफल/ΔABC का क्षेत्रफल = (4/9)2 = 16/81

ΔAMN का क्षेत्रफल = 16 इकाई और ΔABC का क्षेत्रफल = 81 इकाई

अब, चतुर्भुज MBCN का क्षेत्रफल = ΔABC का क्षेत्रफल - ΔAMN का क्षेत्रफल

⇒ 81 - 16 इकाई = 130 सेमी2

⇒ 65 इकाई = 130 सेमी2

⇒ 1 इकाई = 130/65 = 2 सेमी2

∴ ΔAMN का क्षेत्रफल = 16 × 2 = 32 सेमी2
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